以直径400mm,转弯半径500mm,4节90度弯头为例:
1、计算第一节角度:
90/(2(4-1))
=15
2、计算各点素线长度(12等份圆周):
⑴、1-1×(360/12)
=0
400/2×(1-cos0)×tan15+(500-400/2)×tan15
=80.38
⑵、2-1×(360/12)
=30
400/2×(1-cos30)×tan15+(500-400/2)×tan15
=87.48
⑶、3-1×(360/12)
=60
400/2×(1-cos60)×tan15+(500-400/2)×tan15
=107.16
⑷、4-1×(360/12)
=90
400/2×(1-cos90)×tan15+(500-400/2)×tan15
=133.95
⑸、5-1×(360/12)
=120
2×500×tan15
=267.9
267.9/2-400/2×tan15×cos120
=160.76
⑹、6-1×(360/12)
=150
2×500×tan15
=267.9
267.9/2-400/2×tan15×cos150
=180.38
⑺、7-1×(360/12)
=180
2×500×tan15
=267.9
267.9/2-400/2×tan15×cos180
=187.55
如图 看得懂的吧.