90度弯头计算发展开图怎么下样板

2026-01-11 23:54:18
推荐回答(2个)
回答1:

以直径400mm,转弯半径500mm,4节90度弯头为例:

1、计算第一节角度:

90/(2(4-1))

=15

2、计算各点素线长度(12等份圆周):

⑴、1-1×(360/12)

=0

400/2×(1-cos0)×tan15+(500-400/2)×tan15

=80.38

⑵、2-1×(360/12)

=30

400/2×(1-cos30)×tan15+(500-400/2)×tan15

=87.48

⑶、3-1×(360/12)

=60

400/2×(1-cos60)×tan15+(500-400/2)×tan15

=107.16

⑷、4-1×(360/12)

=90

400/2×(1-cos90)×tan15+(500-400/2)×tan15

=133.95

⑸、5-1×(360/12)

=120

2×500×tan15

=267.9

267.9/2-400/2×tan15×cos120

=160.76

⑹、6-1×(360/12)

=150

2×500×tan15

=267.9

267.9/2-400/2×tan15×cos150

=180.38

⑺、7-1×(360/12)

=180

2×500×tan15

=267.9

267.9/2-400/2×tan15×cos180

=187.55

回答2:

如图  看得懂的吧.